Comments on: Find Odd Or Even Numbers

By: Baseer

Baseer — Sat, 15 May 2010 08:57:28 +0000

Its easy but if you provide some visual lesson then it will be more convenient for us

By: sameer dhakal

sameer dhakal — Wed, 17 Feb 2010 18:04:26 +0000

oh thanks

By: shakil

shakil — Wed, 13 Jan 2010 09:25:14 +0000

i want to use a function and inside that function i have to use conditional operator so that i can get the even number that are divided by 2 with a remainder 0.
i have done but i can’t get the exact output in echo command.
can anyone advise me?

By: Anthoni Raj

Anthoni Raj — Mon, 23 Nov 2009 04:08:19 +0000

ur details r very good….

By: Ashish

Ashish — Sun, 16 Aug 2009 19:35:28 +0000

Hi there, Can you provide a server to execute these codes ?

By: xgee

xgee — Mon, 03 Aug 2009 00:19:08 +0000

hi – you need you use the variable $counter instead of $num on the if statement inside the for-loop.

“if (is_odd($counter)) {“

By: Jakob

Jakob — Wed, 29 Jul 2009 01:11:34 +0000

First a complaint, then a compliment. 7 % 2 = 1, not .5; You’re confusing division with modulo (7 / 2 = 3.5). With 7 modulo 2, 2 goes into 7, 3 complete times, with a remainder of 1. Try it: echo (7%2); Also, i’ve never seen someone explain binary quite as well, your graphics were very helpful in this purpose. Good job.

By: suman

suman — Mon, 22 Jun 2009 11:08:52 +0000

hi
thankx sir i am able to learn php in easier way.